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- How many grams of \text {NH}_4\text {OH} do I need to make . . . - Socratic
"6 3072 g" >>"Molarity" = "Moles of solute" "Volume of solution (in litres)" "0 45 M" = "n" "0 4 L" "n = 0 45 M × 0 4 L = 0 18 mol" You need "0 18 mol" of "NH"_4"OH" Molar mass of "NH"_4"OH" is "35 04 g mol" Mass of solute = 0 18 cancel"mol" × "35 04 g" cancel"mol" = "6 3072 g"
- What is the product of the following reaction? 1)CH_3 OH - Socratic
These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
- On the hydrolysis of esters according to the reaction: HCOO . . . - Socratic
HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each product is in aqueous solution If NaOH is added, then we have increased the concentration of hydroxide ions The reaction will shift left to re-equilibrate and consume the excess OH^- Pressure will have
- What is the #pH# of a saturated solution of calcium . . . - Socratic
What is the #pH# of a saturated solution of calcium hydroxide, given that #K_"sp" (Ca (OH)_2)-=1 30xx10^-6#?
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Calculating the concentration of excess HCL in E - Socratic
The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical
- Question #d6b18 - Socratic
We want the standard enthalpy of formation for Ca (OH)_2 Thus, our required equation is the equation where all the constituent elements combine to form the compound, i e : Ca +H_2+O_2->Ca (OH)_2 Let us now write down the given equations: [The first equation mentioned is incorrect, and so I have revised it ] (1) 2H_2 (g) + O_2 (g)->2H_2O (l) and DeltaH_1=-571 66 kJmol^-1 (2) CaO (s) + H_2O (l
- Question #9f499 - Socratic
Explanation: Your starting point here is the pH of the solution More specifically, you need to use the given pH to determine the concentration of hydroxide anions, #"OH"^ (-)#, present in the saturated solution
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