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- How can I determine a Python variables type? - Stack Overflow
type only returns the type of an object (its class) We can use it to check if the variable is of type str isinstance checks if a given object (first parameter) is: an instance of a class specified as a second parameter For example, is variable an instance of the str class? or an instance of a subclass of a class specified as a second parameter
- How to compare type of an object in Python? - Stack Overflow
# check if x is a regular string type(x) == str # check if x is either a regular string or a unicode string type(x) in [str, unicode] # alternatively: isinstance(x, basestring) # check if x is an integer type(x) == int # check if x is a NoneType x is None Note the last case: there is only one instance of NoneType in python, and that is None
- How to check type of object in Python? - Stack Overflow
type() with one argument returns the type or class of the object So if you have a = 'abc' and use type(a) this returns str because the variable a is a string If b = 10, type(b) returns int See also python documentation on type()
- python - How can I check if an object has an attribute? - Stack Overflow
You can check whether object contains an attribute by using the hasattr built-in method For an instance, if your object is a and you want to check for attribute stuff: >>> class a: stuff = "something" >>> hasattr(a,'stuff') True >>> hasattr(a,'other_stuff') False
- python - How to check whether a variable is a class or not? - Stack . . .
The short answer is that in Python the type of class is type If it is an object, then the type will be something else Strangely enough after playing around with it, I have discovered that below is all you need Why there is not a built-in method for one line of code, I don't know
- Determine if Python variable is an instance of a built-in type
The proper way to determine if a given object is an instance of a buil-in type class is to check if the type of the object happens to be defined in the module __builtins__ def is_builtin_class_instance(obj): return obj __class__ __module__ == 'builtins'
- How to test NoneType in python? - Stack Overflow
Since None is the sole singleton object of NoneType in Python, we can use is operator to check if a variable has None in it or not Quoting from is docs, The operators is and is not test for object identity: x is y is true if and only if x and y are the same object x is not y yields the inverse truth value
- Python: how to determine if an object is iterable?
Pythonic programming style that determines an object's type by inspection of its method or attribute signature rather than by explicit relationship to some type object ("If it looks like a duck and quacks like a duck, it must be a duck ") By emphasizing interfaces rather than specific types, well-designed code improves its flexibility by
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