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- What is the Integral of 2^(x)? - Physics Forums
The integral of 2^x can be solved using the relationship between derivatives and integrals The derivative of 2^x is ln(2) * 2^x, which leads to the conclusion that the anti-derivative is (1 ln(2)) * 2^x
- Solving Integrals for e^-ax^2: (i), (ii) (iii) - Physics Forums
Solving Integrals for e^-ax^2: (i), (ii) (iii) sanitykey Nov 9, 2006 Integrating
- What is the Integral of -e^ (-x)? - Physics Forums
The integral of -e^ (-x) is derived using u-substitution, where u = -x, leading to the result -e^ (-x) + C The negative sign arises because the derivative of -x is -1, thus requiring division by -1 during integration The discussion emphasizes that integration can be viewed as the reverse of differentiation, which simplifies the process
- Integral of 1 (x^2 + 2) dx - 2) dx ? • Physics Forums
Mentor note: Moved from technical section, so missing the homework template How do you integrate this? $$\int \frac {1} {x^2 + 2} dx$$ My attempt is $$\ln
- Can the Volume of a Sphere be Calculated by . . . - Physics Forums
i noticed that if i integrate 2 \\pi r i get \\int 2 \\pi r dr=\\pi r^2 i figured its because the area of a circle can be seen as the sum of circumference's of circles with radius 0 to radius r i was thinking if the half volume of a ball also be seen as made from the sum of areas of circules
- How do you integrate (r^2-x^2)^ (1 2) with a constant r?
Jun 18, 2004 #1 FUNKER 120 0 how would you integrate (r^2-x^2)^ (1 2) where r is constant thanks peace Mathematics news on Phys org AI math genius delivers 100% accurate results Robust 'Huber mean' for geometric data protects against noise and outliers Diverse particles form identical geometric patterns when confined, model reveals
- How can the formula for integrating 1 (x^2+y^2)^(3 2) be derived?
Well, so I really want to integrate what's shown in the title: i e \\int \\frac{dx}{(x^2+y^2)^\\frac{3}{2}} Now, I know there are quite a few straightforward answers to this But what I really want is how people who do math got this formula in the first place I don't just want a formula that
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